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Home/ Questions/Q 6546291
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T11:41:23+00:00 2026-05-25T11:41:23+00:00

I have a for each loop in vb.net for this particular example there are

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I have a for each loop in vb.net for this particular example there are 2 items in list but after the first item the loop exits are there errors in the code

Public Function findUserID(ByVal list As List(Of KeyValuePair(Of String, String)), ByVal value As String)
    Dim id As String = String.Empty
    For Each kvp  In list
        If (kvp.Value = value) Then
            id = kvp.Key
        End If
    Next
    Return id
End Function
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  1. Editorial Team
    Editorial Team
    2026-05-25T11:41:24+00:00Added an answer on May 25, 2026 at 11:41 am

    Try to use this:

    dim kvp as KeyValuePair
    kvp = list.Find(p=>p.Value = value))
    if kvp = null then return "" else return kvp.Key
    

    One user told me to modify it in this way:

    dim kvp = list.Find(Function(e) e.Value = value)
    If kvp Is Nothing Then Return "" Else Return kvp.Key
    

    Sorry if this code has some error, but I cannot try and I usually write in C#.
    So my code (in C#) would be:

    KeyValuePair kvp = list.Find(p=>p.Value == value));
    return kvp == null ? "" : kvp.Key;
    
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