Question

I have a for loop such as:

staff = Staff.objects.all().order_by('person__full_name')
for k in staff:
    categ = k.staff_job_categories.all()[1]
    if categ.name == unicode("xxx","utf-8"):
        t = categ.name

But for categ = k.staff_job_categories.all()[1]
I get an List out of index Error.

Any ideas?

Answer 1

Seems print len(k.staff_job_categories.all()) will output 0 or 1 because there are no staff job categories for this item or just only one category exists (which has index 0 and not 1).

So if you’re interesting exactly in second category if it exists your code can be changed to

staff = Staff.objects.all().order_by('person__full_name')
for k in staff:
    categories = k.staff_job_categories.all()
    if len(categories) < 2:
        continue
    categ = categories[1]
    if categ.name == unicode("xxx","utf-8"):
        t = categ.name