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Home/ Questions/Q 6128511
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T16:38:07+00:00 2026-05-23T16:38:07+00:00

I have a form as follows: <form id=myformid name=myformname method=get action=form1.php onsubmit=return checkDependant()> <fieldset>

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I have a form as follows:

<form id="myformid" name="myformname" method="get" action="form1.php" onsubmit="return checkDependant()">
<fieldset>
<label>Food:</label>
<select name="Foods" size="1" class="search_input" id="selectid">
<option value="">Food Type</option>
<option value="Banana">Banana</option>
<option value="Apple">Apple</option>
<option value="Orange">Orange</option>
<option value="Pizza">Pizza</option>
</select>
</fieldset>
<input type="submit" name="searchname" id="searchid" value="" />
</form>

The form should always be processed by form1.php except if “Orange” is selected, then the form should be processed by form2.php. Can this be done using Javascript / JQuery?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T16:38:07+00:00Added an answer on May 23, 2026 at 4:38 pm

    Something like this:

    http://jsfiddle.net/EtbvE/

    $("#myformid").submit(function(){
        if($("#selectid").val()==="Orange"){
            $(this).attr("action","form2.php");   
        }
    });
    
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