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Home/ Questions/Q 7695213
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T21:29:51+00:00 2026-05-31T21:29:51+00:00

I have a form builder class which inherits from AbstractType and I need to

  • 0

I have a form builder class which inherits from AbstractType and I need to resolve a path like this:

$uri = $router->generate('blog_show', array('slug' => 'my-blog-post'));

Since the class is not a child of Controller I have no access to the router. Any ideas?

What about passing the router to the class on construction time?

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  1. Editorial Team
    Editorial Team
    2026-05-31T21:29:52+00:00Added an answer on May 31, 2026 at 9:29 pm

    You can pass the router service via constructor to your form type. Register your form as a service with the form.type tag and inject the router service to it.

    <?php
    namespace Vendor\Bundle\AppBundle\Form\Type;
    
    use Symfony\Component\Form\AbstractType;
    use Symfony\Bundle\FrameworkBundle\Routing\Router;
    
    class PostType extends AbstractType
    {
        /**
         * @var Router
         */
        private $router;
    
        /**
         * @param Router
         */
        public function __construct(Router $router)
        {
            $this->router = $router;
        }
    
        /**
         * @return string
         */
        public function getName()
        {
            return 'post';
        }
    
        // ...
    }
    

    Register it as a service:

    services:
        form.type.post:
            class: Vendor\Bundle\AppBundle\Form\Type\PostType
            arguments: [ @router ]
            tags:
                - { name: form.type }
    

    And use it in your controller like this:

    public function addAction(Request $request)
    {
        $post = new Post();
        $form = $this->createForm('post', $post);
    
        // ...
    }
    

    Since you registered your form type as a service with the form.type tag, you can simply use its name instead of new PostType(). And you can access the router service as $this->router in your type.

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