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Home/ Questions/Q 7615449
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T02:38:50+00:00 2026-05-31T02:38:50+00:00

I have a form: <form name=char-add id=char-add action=added.php method=post onsubmit=charAddValidate()> <input type=text name=Name id=Name

  • 0

I have a form:

<form name="char-add" id="char-add" action="added.php" method="post"
 onsubmit="charAddValidate()">
    <input type="text" name="Name" id="Name" onkeyup="charNameSelected()" autocomplete="off" />
</form>

charNameSelected() simply shows the next div when something is typed into the box.

Then some Javascript code that acts on the form:

function charAddValidate() {
    x = document.forms["char-add"]["Name"].value;
    if (x == "" || x == null) {
        alert("Name is required");
        return false;
    } else {
        return true;
    }
}

The code works, if the name is left blank it does indeed give the alert box, but if I ok this, it continues to submitting the form anyway, resulting in my php validation error 😉

Where am I going wrong (I want it not to submit the page when js validation fails). I know i’m probably missing something obvious to someone else 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-31T02:38:51+00:00Added an answer on May 31, 2026 at 2:38 am

    try adding return:

    … onsubmit="return charAddValidate()">
    
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