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Home/ Questions/Q 7186245
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T18:35:28+00:00 2026-05-28T18:35:28+00:00

I have a form I’d like to submit as JSON via jQuery AJAX, so

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I have a form I’d like to submit as JSON via jQuery AJAX, so that I can read it into a temporary table on the server-side using one my programming language’s native methods (OpenEdge using READ-JSON). An example of the JSON my form needs to produce is:

{"ttOrder": [
  {
    "cProduct": "prod01",
    "iQty": 123
  },
  {
    "cProduct": "prod02",
    "iQty": 456
  }
]}

My form is made up of a table containing rows of product information, product code, description etc. and a quantity input field, e.g.

<input id="prod01" name="prod01" value="0">

From searching around Stack Overflow I found a couple of suggestions that looked like they might help, as I think I need to serialise the form:

(function( $ ){
    $.fn.serializeJSON=function() {
        var json = {};
        jQuery.map($(this).serializeArray(), function(n, i){
            json[n['name']] = n['value'];
        });
        return json;
    };
})( jQuery );

var obj = {"ttOrder": [$('#prodform').serializeJSON() ]};

And then in the $.ajax call use

...
data: JSON.stringify(obj),
...

However, this gives the following:

{"ttOrder": [
  {
    "prod01": "123",
    "prod02": "456"
  }
]}

I think that all the code above is doing is creating a JSON string comprising of the input name and value as a key & value pair, but I don’t have the know-how to change the code to get me what I require.

I think that what I’m trying to achieve is to have an array of objects where the name of the array is always ttOrder (maps to my temp-table name), the first entry of an object is the product code (always cProduct – maps to my temp-table field name) with a value of the input’s name, and the second entry of an object is the quantity (always iQty – maps to my temp-table field value).

Please excuse any incorrect terminology I use.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T18:35:29+00:00Added an answer on May 28, 2026 at 6:35 pm

    The first example is close. This should work here:

    (function( $ ){
    $.fn.serializeJSON=function() {
        return jQuery.map($(this).serializeArray(), function(i, n){
            var json = {};
            json['cProduct'] = n['name'];
            json['iQty'] = parseInt(n['value']);
    
            return json;
    
        }).get();
    };
    })( jQuery );
    
    var obj = {"ttOrder": $('#prodform').serializeJSON()};
    
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