Question

I have a form on my site which sends data to some remote site – simple html form.
What I want to do is to use data user enters into form for statistical purposes.
So I instead of sending data to the remote page I send it first to my script which resends it the remote site.

The thing is I need it to behave in exact way the usual form would behave taking user to the remote site and displaying resources.

When I use this code it kinda works but not in the way I want it to:

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $action);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $fields);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
$result = curl_exec($ch);
curl_close($ch);

Problem is that it displays response in the same script. For example if $action is for example:
somesite.com/processform.php and my script name is mysqcript.php it would display the response of “somesite.com/processform.php” inside “mysqcript.php” so all the relative links are not working.
How do I make it to send the user to “somesite.com/processform.php”? Same thing that pressing the button would do?

Leonti

Answer 1

There are several ways to do that. Here’s one of the easiest: just use a 307 redirect.

 header('Location: http://realsite.com/form_url.php', true, 307');

You can do your logging and stuff either before or after header() but if you do it after calling header() you will need to start your script with

ignore_user_abort(true);

Note that browsers are supposed to notify the user that their form is being redirected.