Question

I have a form that contains a Shockwave Flash object. I want that after playing the file or in the middle of it by pressing a key another form is shown. What should I do? Should I use an event?

Here’s the code:

private void Form1_Load(object sender, EventArgs e)
{
    axShockwaveFlash1.Movie = "c:/intro.swf";
    axShockwaveFlash1.Forward();
    axShockwaveFlash1.Play();
    Form2 form2 = new Form2();
    form2.Show();
}

And in Form2:

private void Form2_Load(object sender, EventArgs e)
{
    Form1 form1 = new Form1();
    form1.Close();
}

When I debug both forms are shown but I just want Form2.

Answer 1

You can pass the Form1 instance to the Form2 constructor, and close it there, like:

public Form2(Form1 form1)
{
    InitializeComponents();

    form1.Hide();//hide the control from the user, or close it if it not the main form..
}

Or if you want it to close the form1 instance when a button click then:

private Form1 _form1 = null;
public Form2(Form1 form1)
{
    InitializeComponents();

    _form1 = form1;
}

private void button1_Click(object sender, EventArgs e)
{
    if (_form1 != null)
    {
        _form1.Hide();
    }
}

Initialize the form2 in form1:

axShockwaveFlash1.Movie = "c:/intro.swf";
axShockwaveFlash1.Forward();
axShockwaveFlash1.Play();
Form2 form2 = new Form2(this);//"this here is the form1 instance itself"
form2.Show();