Question

I have a form that displays contact email addresses in text boxes, and drop down selections for titles for those corresponding emails.

TitleSelect1 Email1
TitleSelect2 Email2 ….

the emails have a title_id set, and the select list selects the existing Title. This works fine for the first contact, but the rest will only display the email address, the title dropdown is empty.

<?php

while ($row2 = mysql_fetch_array($Contact_list)) {
    ?>
<tr>
    <td align="right"><select id="Contacts_title" name="Contacts_title[]">
        <?

        while ($row3 = mysql_fetch_array($title_list)) { //put the contact titles into an array

            if ($row3['title_id'] == $row2['title_id']) {
                ?>
                <option value="<? echo $row3['title_id'] ?>" selected="true"><? echo $row3['title'] ?>!</option>';
                <?
            }

            else {
                ?>
                <option value="<? echo $row3['title_id'] ?>"><? echo $row3['title'] ?> </option>';
                <?
            }
        }

        ?>
    </select>
    </td>
    <td align="left"><input type="text" id="Contacts" name="Contacts[]" value="<? echo $row2['email'] ?>"/></td>
</tr>
<?
    $count++;
} 

Answer 1

mysql_fetch_array() only goes through the results of a given query once. Since you’re not executing the title_list query every time though your contact list loop, it’s still at the end of the query results when you start every iteration after the first.

What you need to do is take all the results from your title_list query, put them into an array, and iterate over that for each of your contacts.

---

Here’s a general example of how you’d do this (with extraneous bits trimmed out):

$contact_list = //some query
$title_list = //some query

$titles = array();
while($title_ar = mysql_fetch_array($title_list)) {
  $titles[] = $title_ar;
}

while($contact_ar = mysql_fetch_array($contact_list)) {
    // some stuff
    foreach($titles as $title) {
        // do something with each title
    }
}