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Editorial Team
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Asked: 2026-05-16T18:56:54+00:00

I have a form which contains a select named Client_ID as well as some

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I have a form which contains a select named Client_ID as well as some other text inputs. What I need is that when a user selects a Client_ID, my fields Address1, Address 2 etc should be populated with the result of a database query along the lines of 

SELECT Address1, Address2 from Client where Client_ID = Client_ID

I’m aware this is somewhat of a noob question, but would really appreciate some help on the simplest and best way to do this.

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1 Answer

  1. Editorial Team

    You should do something like this with jQuery + JSON

    First of all download jquery from here and include it in your application.

    If home.php, your downloaded jquery file(jquery-1.4.2.min.js) and getData.php are in the same folder then your home.php will be look like this:

    home.php (file that contain your form)

    <html>

<head>

    <script type="text/javascript" src="jquery-1.4.2.min.js"></script>

    <script type="text/javascript">
    jQuery(document).ready(function(){
        jQuery('#Client_ID').live('change', function(event) {
            $.ajax({
                url     : 'getData.php',
                type    : 'POST',
                dataType: 'json',
                data    : $('#myform').serialize(),
                success: function( data ) {
                       for(var id in data) {        
                              $(id).val( data[id] );
                       }
                }
            });
        });
    });
    </script>

</head>

<body>

    <form id='myform'>
     <select name='Client_ID' id='Client_ID'>
       <option value=''>Select</option>
       <option value='1'>Client 1</option>
       <option value='2'>Client 2</option>
     </select>

     <input type='text' name='address1' id='address1'>
     <input type='text' name='address2' id='address2'>

     <select name='gender' id='gender'>
        <option value=''>Select</option>
        <option value='1'>Male</option>
        <option value='2'>Female</option>
     </select>

    </form>

</body>


</html>

    getData.php

    <?php

$clientId = $_POST['Client_ID']; // Selected Client Id

$query  = "SELECT Address1, Address2 from Client where Client_ID = $clientId";
$result = mysql_query($query);
$row = mysql_fetch_array($result, MYSQL_ASSOC)

$add1 = $row[Address1];
$add2 = $row[Address2];
$gender = 1;

$arr = array( 'input#address1' => $add1, 'input#address2' => $add2, 'select#gender' => $gender );
echo json_encode( $arr );

?>

    I have tested this code on my machine and it is working.

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