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Home/ Questions/Q 8047271
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T06:03:05+00:00 2026-06-05T06:03:05+00:00

I have a form with field <input type=file name=file size=100 value=> if this field

  • 0

I have a form with field

<input type="file" name="file" size="100" value="">

if this field is empty I want to skip trying to upload the image (because there isnt one) and only update any information that has changed. If an image is present upload it and update the mysql database.

This code was only working if a new image was being uploaded. Added the if(!empty but now the wrong file type code is popping when the form field is left blank?

// connect to datebase
require "master.db.php";

if(!empty($_FILES['file']))
    {
      if ( file types )
          {
           // upload the file
          }
       else
          {
           // wrong file type
                 die;
           }
     }

else {
    // update other data in mysql database
    $sql="UPDATE `characters` SET test='test' WHERE ID='$id'";
    $result=mysql_query($sql);

    // if successfully updated mysql.
       if($result){
          echo "<b>Update successful</b> <br />";
          echo "<a href='../test.html'>View result</a>";
          touch('../master.html');
          clearstatcache();
          }

        else {
             echo "Whoops: " . mysql_error(); ;
              }
    mysql_close();
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T06:03:07+00:00Added an answer on June 5, 2026 at 6:03 am

    use this

    if(!$_FILES['file']){ 
         echo "file is empty" 
    }
    

    instead of

    if(empty($_POST['file']))
    

    finally

        if(!empty($_FILES['file'])){ 
         //file has something
        }
       else{
         //either file is empty or filed is not set
       }
    
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