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Home/ Questions/Q 9263177
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T13:31:23+00:00 2026-06-18T13:31:23+00:00

I have a form with rows which are populated from a table. Each row

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I have a form with rows which are populated from a table. Each row has a “checkbox” which the user can check or not.

When the form is submitted I want to be able to read which checkbox have been selected and insert the result in to a data table.

My code so far
FORM:

<form method="post" name="form1" action="<?php echo $editFormAction; ?>">
<table
<?php do { ?>
<tr>
<td>input type="text" name="InspectRoomNo" value="<?php print $row_InspectItems['AuditItemNo']; ?>"></td>
<td>php echo $row_InspectItems['AuditItem']; ?>td>
<td>input name="check[]" type="checkbox"  ></td>
</tr>
<?php } while ($row_InspectItems = mysql_fetch_assoc($InspectItems)); ?>
<input type="submit" value="Insert record">
</table>

The insert: fetchs $Items from table

while($row = mysql_fetch_assoc($Items))
{
$array[] = $row['AuditItem'];
}


foreach($array as $id) {
$AuditItemID = mysql_real_escape_string($id);

if(isset($_POST['check'])){
$Checked = mysql_real_escape_string($_POST['check'][$row]);
}
}

The problem I am having is the returned values for all the checkbox is true, even if a checkbox was not selected.

Can anyone help me sort this issue.

Many thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T13:31:24+00:00Added an answer on June 18, 2026 at 1:31 pm

    Do it like this:

    if(!empty($_POST['check'])) {
        foreach($_POST['check'] as $check) {
            echo $check; 
        }
    }
    
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