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Home/ Questions/Q 8394573
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Editorial Team
  • 0
Editorial Team
Asked: June 9, 20262026-06-09T20:05:45+00:00 2026-06-09T20:05:45+00:00

I have a form with two text boxes and two buttons (one submit button,

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I have a form with two text boxes and two buttons (one submit button, one button). when I call click the button, it has to make an ajax call with data “CheckRegistration”. Finally, it will call ViewRegisteredStudents() function. I am expecting the “resultVal” stirng to be returned to ajax call but it is returning the “resultVal” string and form (two textboxes, two buttons).

 $(document).ready(function(){

             $(':button').click(function(){
                  $.ajax({
                      Url:"SkiiTripDB.php",
                      type:"POST",
                      data:{call:'CheckRegistration'},
                      dataType:"html",
                      success:function(data){
                             $('div#registeredStudents').html(data);
                      }
                  });
              });

          });

      if(isset($_POST['call']))
        {
                $call=$_POST['call'];

                  $connection=IsDatabaseConnected($strServer,$strUsername,$strPassword,$strDatabaseName);
                 switch($call)
                 {
                      case 'CheckRegistration':ViewRegisteredStudents();
                                                break;
                 }
                 closeDatabaseConnection($connection);   
         }

function ViewRegisteredStudents()
        {
           $resultVal="";
           $resultVal.="<table  border='2'>";
           $resultVal.="<tr>";
           $resultVal.="    <th>Student Name</th>";
           $resultVal.="     <th>Student Class</th>";
           $resultVal.=" </tr>";

           // Query database
           $strSqlQuery="SELECT sSName, sClass FROM tripregistration";

           $result=mysql_query($strSqlQuery);

           while($row=mysql_fetch_array($result))
           {
               $resultVal.="<tr>";
                $resultVal.="<td>".$row['sSName']."</td>";
                $resultVal.="<td>".$row['sClass']."</td>";
               $resultVal.="</tr>";
           }
                $resultVal.="</table>";

              echo $resultVal;

            }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T20:05:46+00:00Added an answer on June 9, 2026 at 8:05 pm

    In your AJAX call see the parameter
    Url:”SkiiTripDB.php” in Url U is capital convert it to lowercase.

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