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Home/ Questions/Q 4032782
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Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T11:45:52+00:00 2026-05-20T11:45:52+00:00

I have a form with various fields the user need to feel out with

  • 0

I have a form with various fields the user need to feel out with the option of attaching number of images:

 <?php
    $num = 0;
    while($num < $num_uploads)
    {
        echo '<div><input name="userfile[]" type="file" /></div>';
        $num++;
    }
 ?>

After submission it creates a table in the database, called “album” which looks something like this:

function create_album($params)
{
   db_connect();

     $query = sprintf("INSERT INTO albums set
                                     albums.title = '%s',
                                                                 albums.email = '%s',
                                                                 albums.discuss_url = '%s',
                                                                 albums.theme_id = '%s',
                                                                 albums.fullname = '%s',
                                                                 albums.description = '%s',
                                                                 created_at = NOW()",
                                                                 mysql_real_escape_string($params['title']),
                                                                 mysql_real_escape_string($params['email']),
                                                                 mysql_real_escape_string($params['discuss_url']),
                                                                 mysql_real_escape_string($params['theme_id']),
                                                                 mysql_real_escape_string($params['fullname']),
                                                                 mysql_real_escape_string($params['description'])
                                                                 );

     $result = mysql_query($query);
     if(!$result)
     {
          return false;
     }

     $album_id = mysql_insert_id();

     return $album_id;
}   

I want the files, however to go to “images” table and link to the correct album.

$create_album = create_album($_POST['album']);

                   mysql_query( "INSERT INTO images(`name`,`album_id`) VALUES('$newName', '$create_album')" );

I am having the problem is attaching those multiple images(the user can choose to submit one or 2, or 3 files) with one form submission to one album. Right now, if the user submit 3 files it creates 3 albums with every form submission.

Finally, this is my database structure:

CREATE TABLE `albums` (
  `id` int(11) NOT NULL auto_increment,
  `title` varchar(50) NOT NULL,
  `fullname` varchar(40) NOT NULL,
  `discuss_url` varchar(150) NOT NULL,
  `email` varchar(100) NOT NULL,
  `created_at` datetime NOT NULL,
  `theme_id` int(11) NOT NULL,
  `description` int(11) NOT NULL,
  `vote_cache` int(11) NOT NULL,
  PRIMARY KEY  (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;



CREATE TABLE `images` (
  `id` int(11) NOT NULL auto_increment,
  `album_id` int(11) NOT NULL,
  `name` varchar(30) NOT NULL,
  PRIMARY KEY  (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=18 ;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:45:53+00:00Added an answer on May 20, 2026 at 11:45 am

    I just wanted to run quick update on this issue. Perhaps I didn’t give enough info which was important to see the problem. This article explains it very well. Basically the album was created each time the file was submitted, but not the form.

    So here is my form(working):

    <?php if (!isset($_POST['btnSubmit'])) { ?>
    <form action="index.php?view=create" method="post" enctype="multipart/form-data">
        <fieldset>
         <div>
                 <label><b>Title:</b></label>
    
                 <input name="album[title]" size="40" type="text" value="" class="textfield" />
                 </div>
    
                <div>
               <label><b>Fullname</b></label>
               <input name="album[fullname]" size="40" type="text" value="" class="textfield" />
                </div>
    
                <div>
    
               <label><b>Attach Photo</b> </label>
                    <input type="hidden" name="" value="" />
     <?php
        $num = 0;
        while($num < $num_uploads)
        {
            echo '<div><input name="userfile[]" type="file" /></div>';
            $num++;
        }
     ?>
    

    Here is php (I cut out some of it so it is easier):

        //If form was submitted
        if (isset($_POST['btnSubmit'])) {
    
        create_album($_POST['album']);
        $find_album_id = mysql_insert_id();
    
            /*** check if a file has been submitted ***/
            if(isset($_FILES['userfile']['tmp_name']))
            {
                /** loop through the array of files ***/
                for($i=0; $i < count($_FILES['userfile']['tmp_name']);$i++)
                {
    
                  $ext = strrchr($imgName, ".");
    
                   // then create a new random name
                  $newName = md5(rand() * time()) . $ext;
    
                          if (is_image_types($_FILES['userfile']['type'][$i]) 
                          and is_valid_file_size($_FILES['userfile']['size'][$i])
                          and is_uploaded_file($_FILES['userfile']['tmp_name'][$i])
                          and is_valid_width_height($_FILES['userfile']['tmp_name'][$i])
                       )
                      {    
    
                           mysql_query("INSERT INTO images(name, album_id) VALUES('$newName', '$find_album_id')") ; 
                           copy($_FILES['userfile']['tmp_name'][$i], './photos/'.$original_dir.'/' .$newName.'.jpg');
    
                }
    
                else
                {
             $warning = "Click back error uploading file. 
                                 Please make sure your file is a JPEG and less than 1MB";
                }
            }
        }
    
        }   
    
        break;
    }
    

    I hope it helps anyone who is looking…

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