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Home/ Questions/Q 96719
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Editorial Team
Asked: May 10, 20262026-05-10T23:52:01+00:00 2026-05-10T23:52:01+00:00

I have a funciton that I am currently using to show a hidden div.a_type

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I have a funciton that I am currently using to show a hidden div.a_type

How can I modify this code so that instead of fading in the hidden div, I can add the new div to the DOM

 jQuery(function(){   // Add Answer      jQuery('.add_answer').click(function(){       if(count >= '4'){         alert('Only 4 Answers Allowed');         }else{       var count = $(this).attr('alt');       count++;       $(this).parents('div:first').find('.a_type_'+count+'').fadeIn();       $(this).attr('alt', count);     }      });   }); 

Ok, now that i have this sorted out, i have one more question,

I have another function that removes the inserted div’s if a button is clicked. It’s not working now that the additional divs are not loaded into the dom on pageload. How can i trigger the function to remove these now?

jQuery(function(){ // Hide Answer

jQuery('.destroy_answer').click(function(){   $(this).parents('div:first').fadeOut(function (){ $(this).remove() });    var count = $(this).parents('div:first').parents('div:first').find('.add_answer').attr('alt');    count--;    $(this).parents('div:first').parents('div:first').find('.add_answer').attr('alt', count);  });  

});

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1 Answer

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  1. 2026-05-10T23:52:02+00:00Added an answer on May 10, 2026 at 11:52 pm

    How about adding it after the last div.

    $('.a_type:last').insertAfter('<div class='a_type'>content</div>'); 

    edit
    You can get the information through a AJAX call to somefile.php, somefile should then return the content you want in the div:

    $.get('path/to/somefile.php', function(data){  $('.a_type:last').insertAfter('<div class='a_type'>' + data + '</div>'); }); 

    Somefile.php should be something like this:

    <?php  session_start();  $sessiondata = $_SESSION['data'];  echo 'Whatever you type here will come inside the div bla bla $sessiondata'; ?> 

    edit
    Okay, try this:

     jQuery(function(){ // Add Answer  jQuery('.add_answer').click(function(){   if(count >= '4'){     alert('Only 4 Answers Allowed');     }else{   var count = $(this).attr('alt');   count++;   $('.a_type_'+count-1+'').insertAfter('         Place content back here');   $(this).attr('alt', count); }  });  }); 

    Just mix in the AJAX if you still need it.

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