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Home/ Questions/Q 7890541
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T06:22:52+00:00 2026-06-03T06:22:52+00:00

I have a function called workForThread, that takes two arguments, and returns void. I

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I have a function called workForThread, that takes two arguments, and returns void. I would like to thread this function using something like:

thread(workForThread,a,b);

Where a and b are of the appropriate types. The above code does not compile, giving a “too many arguments for call” error (“error C2197: ‘void (__cdecl *)(char *)’ : too many arguments for call”)

How can I resolve this?

Note: I have looked at these two questions, but the resolutions that work there do not seem to work for me. Additionally, I have a feeling there is a way to do it built into c++11, and that is what I am looking for.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T06:22:53+00:00Added an answer on June 3, 2026 at 6:22 am

    When using C++11 you could use a lambda function which may use (non-formal) parameter of the context. “Capturing”

    Something like

    void doIt (int a, int b) {  // do something, your workForThread
    }
    
    ..
    int a = 1;
    int b = 2;
    
    std:thread r ([=](){doIt (a, b); return 1;});
    

    When only calling a single function juanchopanza answer may be somewhat more efficient since no new function will be created.

    The lambda version allows you to configure more. Let say you are starting threads which calls in the end 2 functions out of 3. juanchopanza approach would require NAMED functions for each permutation.

    At the moment I consider the difference of both approaches to be mostly a matter of taste.

    When you like to read more about lambda functions

    What is a lambda expression in C++11?

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