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Home/ Questions/Q 9135165
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T08:47:19+00:00 2026-06-17T08:47:19+00:00

I have a function in JavaScript to get the difference between two times: function

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I have a function in JavaScript to get the difference between two times:

function get_time_difference(laterDate) {
    var earlierDate = new Date();//Now
    var nTotalDiff = laterDate.getTime() - earlierDate.getTime();
    var oDiff = new Object();

    oDiff.days = Math.floor(nTotalDiff / 1000 / 60 / 60 / 24);
    nTotalDiff -= oDiff.days * 1000 * 60 * 60 * 24;

    oDiff.hours = Math.floor(nTotalDiff / 1000 / 60 / 60);
    nTotalDiff -= oDiff.hours * 1000 * 60 * 60;

    oDiff.minutes = Math.floor(nTotalDiff / 1000 / 60);
    nTotalDiff -= oDiff.minutes * 1000 * 60;

    oDiff.seconds = Math.floor(nTotalDiff / 1000);

    if (0 == oDiff.minutes && 0 == oDiff.hours) {
        //Do Something
    }
    return oDiff.minutes;
}

When times are equal I need to run a particular function,

my problem is that sometimes he returns 59 minutes, while it should return 0 ..

Why is this happening? How can I fix this?

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  1. Editorial Team
    Editorial Team
    2026-06-17T08:47:20+00:00Added an answer on June 17, 2026 at 8:47 am

    I fix it this way:

    function get_time_difference(laterDate) {
    
    var earlierDate = new Date(); //Now
    var oDiff = new Object();
    
    oDiff.days = laterDate.getDate() - earlierDate.getDate();
    oDiff.hours = laterDate.getHours() - earlierDate.getHours();
    oDiff.minutes = laterDate.getMinutes() - earlierDate.getMinutes();
    oDiff.seconds = laterDate.getSeconds() - earlierDate.getSeconds();
    
    if (0 == oDiff.minutes && 0 == oDiff.hours) {
    //Do Something
    }
       return oDiff.minutes;
    }
    
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