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Home/ Questions/Q 3433976
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T07:38:30+00:00 2026-05-18T07:38:30+00:00

I have a function like below void functionA(unordered_map<string, classA*>* arg1); I need to pass

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I have a function like below

void functionA(unordered_map<string, classA*>* arg1);

I need to pass in

unordered_map<string, shared_ptr<classA>>

How could I pass in the container with shared_ptr to the function which takes in a container of raw pointer? I am using C++0x here.

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-18T07:38:31+00:00Added an answer on May 18, 2026 at 7:38 am

    Since you asked, here’s what a template might look like for this function:

    template <typename MAP_TYPE>
    void functionA(const MAP_TYPE& arg1)
    {
        // Use arg1 here
    }
    

    You could use a pointer and/or make it non-const if you must. As long as the map passed in uses a compatible key type and some kind of pointer to the right type as a value, it should compile and run. Whether the pointer is a native pointer or a smart pointer will likely not make a difference, depending on how you used it in your function implementation.

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