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Home/ Questions/Q 8889461
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T22:16:10+00:00 2026-06-14T22:16:10+00:00

I have a function start with two parameters in module mymodule. How can I

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I have a function start with two parameters in module mymodule. How can I run this function from command line.

I try this:

erl -name myname@myserver.com -s mymodule start 5 10

But It raises error:
{“init terminating in do_boot”,{undef,[{mymodule,start,[[‘5′,’10’]]},{init,start_it,1},{init,start_em,1}]}}

I want to be able to run this function from a bash file

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  1. Editorial Team
    Editorial Team
    2026-06-14T22:16:11+00:00Added an answer on June 14, 2026 at 10:16 pm

    I think it expects the start function to have arity of one, so in this case it is attempting to call module:start([‘5′,’10’]). So change your start function to accept a list of 2 parameters as in [arg1,arg2]. Also, check out the documentation on the -run and -s flags. -s passes arguments as atoms while -run passes them as strings

    -run Mod [Func [Arg1, Arg2, …]](init flag)
    Makes init call the specified function. Func defaults to start. If no arguments are provided, the function is assumed to be of arity 0. Otherwise it is assumed to be of arity 1, taking the list [Arg1,Arg2,…] as argument. All arguments are passed as strings. See init(3).

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