Question

I have a function symbol_scan(integer) that returns a table with three columns: schema, table, count.

I can perform a selection query on it like this:

> SELECT name, symbol_scan(id), FROM symbols;
       name       |        symbol_scan
------------------+--------------------------
 MY_FIRST_SYMBOL  | (public,random,1)
 MY_SECOND_SYMBOL | (public,another_table,1)
 UNIVERSAL        | (public,international,5)

Is it possible to use another query such that the column names from symbol_scan(id) are extracted, such that the table looks like this?

       name       | schema |     table     | count
------------------+--------+---------------+-------
 MY_FIRST_SYMBOL  | public | random        |   1
 MY_SECOND_SYMBOL | public | another_table |   1
 UNIVERSAL        | public | international |   5

Is there a way to do this?

Note: If I run SELECT * FROM symbol_scan(1) I will of course get three columns, but I don’t know how to put the name in there, apart from putting it in the function itself.

Answer 1

You can do what you want on Postgres using this simple syntax:

SELECT name, (symbol_scan(id)).* 
FROM symbols