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Home/ Questions/Q 8963491
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T16:22:04+00:00 2026-06-15T16:22:04+00:00

I have a function that accepts an array of tables as the parameter and

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I have a function that accepts an array of tables as the parameter and after inner joining them returns the resulted rows.

function myfunc($tables, $join_on) {
 foreach($tables as $table) {
  // build query
 }
}

How do I build the query? for example if $tables = array('table1', 'table2') and $join_on = 'field_x' then it should create the following query:

SELECT * FROM table1 INNER JOIN table2 ON table1.field_x = table2.field_x

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  1. Editorial Team
    Editorial Team
    2026-06-15T16:22:06+00:00Added an answer on June 15, 2026 at 4:22 pm

    You can do something like this :

    function myfunc($tables, $join_on) {
        $mainTable = $tables[0];
        $sql = "SELECT * FROM $mainTable";
        for($i = 1; i<count($tables);$i++) {
            $curTable = $tables[$i];
            $joinField = $join_on[$i-1];
            $sql.= " INNER JOIN $curTable ON $curTable.$joinField = $mainTable.$joinField";
        }
    
        return sql;
    }
    

    Of course you need to add some error checking to ensure that you have at least one table in $tables and always N-1 elements in $join_on where N is the number of tables in $tables

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