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Home/ Questions/Q 8785247
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T21:18:18+00:00 2026-06-13T21:18:18+00:00

I have a function that generates an enumerator in the following manner: def create_example_enumerator(starting_value)

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I have a function that generates an enumerator in the following manner:

def create_example_enumerator(starting_value)
  current = starting_value
  e = Enumerator.new do |y|
    loop do
      current += 1
      y << current
    end
  end
end

The current behavior is pretty straightforward.

> e = create_example_enumerator(0)
#<Enumerator: details>
> e.next
1
> e.next
2
> e.rewind
#<Enumerator: details>
> e.next
3

I would like e.rewind to reset the enumerator back to it’s starting value.
Is there a nice way to do that while still using an infinite enumerator?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T21:18:19+00:00Added an answer on June 13, 2026 at 9:18 pm

    This should work:

    n = Enumerator.new do |y|
      number = 1
      loop do
        y.yield number
        number += 1
      end
    end
    
    n.next #=> 1
    n.next #=> 2
    n.next #=> 3
    n.rewind
    n.next #=> 1
    
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