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Home/ Questions/Q 7004229
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:10:19+00:00 2026-05-27T21:10:19+00:00

I have a function that has a dictionary as input and a value n.

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I have a function that has a dictionary as input and a value n.
Each item in the dictionary is a set with one or more values.
The function should sort the dictionary keys and it should extract and return “n”values.
This function will be executed very often therefore I am trying to optimize it. Any suggestions?

def select_items(temp_dict, n):
  """Select n items from the dictionary"""
  res = []
  sort_keys = sorted(temp_dict.keys())
  count = 0

  for key in sort_keys:
    for pair in temp_dict[key]:
      if count < n:
        res.append(pair)
        count += 1
      else:
        return res

  return res

In this code I have a count and “if statement” to control the number of selected values. Is there a way to optimize this code by using some function in itertools or something else?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:10:19+00:00Added an answer on May 27, 2026 at 9:10 pm

    The answers given so far don’t follow the user’s spec.

    The data is a dictionary of sequences, and the desired result is a list of the first n elements of the dictionary values taken in sorted order by key.

    So if the data is:

    {1: [1, 2, 3], 2: [4, 5, 6]}
    

    then, if n = 5, the result should be:

    [1, 2, 3, 4, 5]
    

    Given that, here’s a script which compares the original function with a (slightly) optimised new version:

    from timeit import timeit
    
    def select_items_old(temp_dict, n):
      res = []
      sort_keys = sorted(temp_dict.keys())
      count = 0
      for key in sort_keys:
        for pair in temp_dict[key]:
          if count < n:
            res.append(pair)
            count += 1
          else:
            return res
      return res
    
    def select_items_new(data, limit):
        count = 0
        result = []
        extend = result.extend
        for key in sorted(data.keys()):
            value = data[key]
            extend(value)
            count += len(value)
            if count >= limit:
                break
        return result[:limit]
    
    data = {x:range(10) for x in range(1000)}
    
    def compare(*args):
        number = 1000
        for func in args:
            name = func.__name__
            print ('test: %s(data, 12): %r' % (name, func(data, 12)))
            code = '%s(data, %d)' % (name, 300)
            duration = timeit(
                code, 'from __main__ import %s, data' % name, number=number)
            print ('time: %s: %.2f usec/pass\n' % (code, 1000000 * duration/number))
    
    compare(select_items_old, select_items_new)
    

    Output:

    test: select_items_old(data, 12): [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1]
    time: select_items_old(data, 300): 163.81 usec/pass
    
    test: select_items_new(data, 12): [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1]
    time: select_items_new(data, 300): 67.74 usec/pass
    
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