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Home/ Questions/Q 8851117
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T13:04:19+00:00 2026-06-14T13:04:19+00:00

I have a function that have to return True if and only if all

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I have a function that have to return True if and only if all the ints in L1 are the lengths of the strings in L2 at the corresponding positions. and the Precondition: len(L1) == len(L2).

EXAMPLE:

>>> are_lengths_of_strs([4, 0, 2], ['abcd', '', 'ef']) 
True

Below is the function:

def are_lengths_of_strs(L1, L2):
    result = True
    for i in range(len(L1)):
        if i in len(L1) != len(L2):
            result = False
    return result

It result in a error. The line if i in len(L1) != len(L2): is the wrong . Can someone help me in this line ??

Obs : I have to use !=

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  1. Editorial Team
    Editorial Team
    2026-06-14T13:04:20+00:00Added an answer on June 14, 2026 at 1:04 pm

    Corrected version of your code:

    def are_lengths_of_strs(L1, L2):
        result = True
        for i in range(len(L1)):
            if L1[i] != len(L2[i]):
                result = False
        return result
    

    Note that this is not pythonic, because you don’t in fact need an index here:

    def are_lengths_of_strs(L1, L2):
        result = True
        for i, l in zip(L1, L2)
            if i != len(l):
                result = False
        return result
    

    Even shorter:

    def are_lengths_of_strs(L1, L2):
        return all(i == len(l)
            for i, l in zip(L1, L2))
    
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