Question

I have a function that I need to call

int (*trytoprint_f)(int val, void *param);

but when I call this function, and put

str name = {"jack", 4};
int age = 2;

client->trytoprint(age, (void *)name));

it gives me an error of “cannot convert to a pointer type : C error”

I know the solution which is basically use a function below
str_dup_ptr(name, ulr->imsi, mem); and it works (I got this function from a framework).

Anyways, I am just confused. So the question is if the function accepts (void *param), and I declare name variable with type str, howso when I cast this “name” variable into void pointer, it returns me this error?

Can anyone help me in understanding why this error happens?

Thank you

Answer 1

You have to convert a pointer to structure to void* not a structure itself. Try this way

client->trytoprint(age, (void *) &name));