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Home/ Questions/Q 6874689
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:13:33+00:00 2026-05-27T04:13:33+00:00

I have a function that I need to pass 4 distinct variables to, and

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I have a function that I need to pass 4 distinct variables to, and these variables values come from an array:

$pagesArray = array(
                   'pre-file1.html' => 'blahblah1',
                   'post-file1.html' => 'blahblah2'
                    );

$file1 = 'blahblah1';

$file2 = 'blahblah2';

$file1Name = 'pre-file1.html';

$file2Name = 'post-file1.html';

How do I assign in a foreach loop when I’m calling the function in the loop too?

I’ve tried this

foreach ($pagesArray as $fileName => $url)
{
    $file1 = file($url);
    $file2 = file($url);
    $file1Name = $key;
    $file2Name = $key;


    compareFiles($file1, $file2, $file1Name, $file2Name);

}

But that doesn’t work because it’s calling the function in the loop and will only loop over after it’s called every time.

NB: the above is only an example, there will be more objects in that array than the two currently shown.

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:13:34+00:00Added an answer on May 27, 2026 at 4:13 am
    list($file1, $file2)         = array_values($pagesArray);
    list($file1Name, $file2Name) = array_keys($pagesArray);
    compareFiles($file1, $file2, $file1Name, $file2Name);
    
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