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Home/ Questions/Q 7029715
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:34:31+00:00 2026-05-28T00:34:31+00:00

I have a function that needs to enumerate an iterator multiple times, but according

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I have a function that needs to enumerate an iterator multiple times, but according to MSDN, “Once you increment any copy of an input iterator, none of the other copies can safely be compared, dereferenced, or incremented thereafter.”

So to make things easier, instead of creating a separate implementation for non-forward-iterators that copies the data and enumerates the copy, I want to restrict my method to only taking in forward iterators, and rejecting input iterators statically.

Right now I have something like:

template<typename It, typename TCallback /*signature: bool(value_type)*/>
bool EnumerateTwice(const It &begin, const It &end, TCallback callback)
{
    for (It it = begin; it != end; ++it)
        if (!callback(*it))
            return false;
    for (It it = begin; it != end; ++it)
        if (!callback(*it))
            return false;
    return true;
}

but nothing restricts It to being a forward iterator.

How do I place that restriction on the templated function? (C++03)

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:34:31+00:00Added an answer on May 28, 2026 at 12:34 am

    You can use SFINAE and replace bool by:

    typename enable_if<
       is_same<typename std::iterator_traits<It>::iterator_category,
               std::forward_iterator_tag>::value,
       bool>::type
    

    You may need to define is_same and enable_if yourself if you don’t want to pull them from Boost or TR1:

    template <typename A, typename B>
    struct is_same { static const bool value = false; };
    
    template <typename T>
    struct is_same<T, T> { static const bool value = true; };
    
    template <bool, typename> struct enable_if { };
    template <typename T> struct enable_if<true, T> { typedef T type; };
    
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