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Home/ Questions/Q 7634237
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T07:07:09+00:00 2026-05-31T07:07:09+00:00

I have a function that removes a key from a map: (defn remove-key [key

  • 0

I have a function that removes a key from a map:

(defn remove-key [key map]
  (into {}
        (remove (fn [[k v]] (#{key} k))
                map)))

(remove-key :foo {:foo 1 :bar 2 :baz 3})

How do i apply this function using multiple keys?

(remove-keys [:foo :bar] {:foo 1 :bar 2 :baz 3})

I have an implementation using loop…recur. Is there a more idiomatic way of doing this in Clojure?

(defn remove-keys [keys map]
  (loop [keys keys
         map map]
    (if (empty? keys)
      map
      (recur (rest keys) (remove-key (first keys) map)))))
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  1. Editorial Team
    Editorial Team
    2026-05-31T07:07:10+00:00Added an answer on May 31, 2026 at 7:07 am

    Your remove-key function is covered by the standard library function dissoc. dissoc will remove more than one key at a time, but it wants the keys to be given directly in the argument list rather than in a list. So you can use apply to “flatten” it out.

    (apply dissoc {:foo 1, :bar 2, :baz 3} [:foo :bar])
    ==> {:baz 3}
    
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