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Home/ Questions/Q 699841
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T03:25:51+00:00 2026-05-14T03:25:51+00:00

I have a function that takes 2 parameters : 1 = XML file, 2

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I have a function that takes 2 parameters : 1 = XML file, 2 = XSLT file, then performs a transformation and returns the resulting HTML.

Here is the function:

/// <summary>
/// Will apply an XSLT style to any XML file and return the rendered HTML.
/// </summary>
/// <param name="xmlFileName">
/// The file name of the XML document.
/// </param>
/// <param name="xslFileName">
/// The file name of the XSL document.
/// </param>
/// <returns>
/// The rendered HTML.
/// </returns>
public string TransformXml(string xmlFileName, string xslFileName)
{
    var xtr = new XmlTextReader(xmlFileName)
                  {
                      WhitespaceHandling = WhitespaceHandling.None
                  };
    var xd = new XmlDocument();
    xd.Load(xtr);

    var xslt = new System.Xml.Xsl.XslCompiledTransform();
    xslt.Load(xslFileName);
    var stm = new MemoryStream();
    xslt.Transform(xd, null, stm);
    stm.Position = 1;
    var sr = new StreamReader(stm);
    xtr.Close();
    return sr.ReadToEnd();
}

I want to change the function not to accept a file for the XML, but instead just an object.
The object is exactly compatible with the xslt, if it was serialized to file. But I don’t want to have to serialize it to a file first.

So to recap : keep the xslt coming from a file, but the xml input should an object I pass and would like to generate the xml from without any file system interaction.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T03:25:52+00:00Added an answer on May 14, 2026 at 3:25 am

    You can serialize the object to a string, load the string into a XmlDocument, and perform the transformation :

    public string TransformXml(object data, string xslFileName)
    {
    
        XmlSerializer xs = new XmlSerializer(data.GetType());
        string xmlString;
        using (StringWriter swr = new StringWriter())
        {
            xs.Serialize(swr, data);
            xmlString = swr.ToString();
        }
    
        var xd = new XmlDocument();
        xd.LoadXml(xmlString);
    
        var xslt = new System.Xml.Xsl.XslCompiledTransform();
        xslt.Load(xslFileName);
        var stm = new MemoryStream();
        xslt.Transform(xd, null, stm);
        stm.Position = 0;
        var sr = new StreamReader(stm);
        return sr.ReadToEnd();
    }
    
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