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Home/ Questions/Q 664685
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:37:36+00:00 2026-05-13T23:37:36+00:00

I have a function that takes a const D3DVECTOR3 *pos , but I have

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I have a function that takes a const D3DVECTOR3 *pos, but I have no reason to declare this beforehand. The most logical solution to me was using new:

Function(
    //other parameters,
    new D3DXVECTOR3(x, y, 0));

but I don’t know how I would go about deleting it, beign intitialized in a function. My next thought was to use the & operator, like so:

Function(
    //other parameters,
    &D3DVECTOR3(x, y, 0));

but I don’t know if this is a valid way to go about doing this. (It doesn’t get an error, but there are a lot of things that don’t give errors that aren’t necassarily good). So should I use new, &, or some other technique I’m overlooking?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:37:36+00:00Added an answer on May 13, 2026 at 11:37 pm

    It’s not possible to directly invoke the address-of operator to the temporary (MSVC will tell you that this is not Standard C++ at higher warning levels, too). Except you may do

    Function(
    //other parameters,
    &(D3DXVECTOR3 const&)D3DXVECTOR3(x, y, 0));
    

    But this is disgusting. Just declare a local variable and pass its address.

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