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Home/ Questions/Q 6548249
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Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T11:55:43+00:00 2026-05-25T11:55:43+00:00

I have a function where I want to display something if the value equals

  • 0

I have a function where I want to display something if the value equals A, C or D.

The problem is if the value is set at B or E, the function is display data in the A.C.D. set in addition to the B or E set.

What am I doing wrong?

$linkp = opensky_featured_image_position(); 

if ( $linkp == 'featuredimg-1' || 'featuredimg-3' || 'featuredimg-4' ) {
    echo '<h1>F - '. opensky_featured_image_position() .'</h1>';
}
if ( $linkp == 'featuredimg-2' ) {
    echo '<h1>L - '. opensky_featured_image_position() .'</h1>';
}

if ( $linkp == 'featuredimg-5' ) {
    echo '<h1>N - '. opensky_featured_image_position() .'</h1>';
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T11:55:44+00:00Added an answer on May 25, 2026 at 11:55 am
    if ( $linkp == 'featuredimg-1' || 'featuredimg-3' || 'featuredimg-4' ) {
        echo '<h1>F - '. opensky_featured_image_position() .'</h1>';
    }
    

    Should be

    if ( $linkp == 'featuredimg-1' || $linkp == 'featuredimg-3' || $linkp == 'featuredimg-4' ) {
        echo '<h1>F - '. opensky_featured_image_position() .'</h1>';
    }
    

    If all the values of $linkkp are defined you could do something like this

    $linkArr = array(
        'featuredimg-1' => 'F',
        'featuredimg-2' => 'L',
        'featuredimg-3' => 'F',
        'featuredimg-4' => 'F',
        'featuredimg-5' => 'N',
    );
    
    $linkp = opensky_featured_image_position(); 
    echo '<h1>'.$linkArr[$linkp].' - '. opensky_featured_image_position() .'</h1>';
    
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