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Home/ Questions/Q 905103
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:09:36+00:00 2026-05-15T16:09:36+00:00

I have a function which accepts a parameter named IV. Is there anyway that

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I have a function which accepts a parameter named IV. Is there anyway that I can explicitly specify the size of the parameter IV to be 16 ?

public AESCBC(byte[] key, byte[16] inputIV)
{

   //blah blah

}

The above is of course not working. Is it possible? I know I can check it inside the function and throw an exception but can it be defined in the function definition ?

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  1. Editorial Team
    Editorial Team
    2026-05-15T16:09:37+00:00Added an answer on May 15, 2026 at 4:09 pm

    You can’t, basically. As Jaroslav says, you could create your own type – but other than that, you’re stuck with just throwing an exception.

    With Code Contracts you could express this in a form which the static checker could help with:

    Contract.Requires(inputIV.Length == 16);
    

    Then the static checker could tell you at build time if it thought you might be violating the contract. This is only available with the Premium and Ultimate editions of Visual Studio though.

    (You can still use Code Contracts without the static checker with VS Professional, but you won’t get the contracts.)

    Plug: Currently the Code Contracts chapter from C# in Depth 2nd edition is available free to download, if you want more information.

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