Question

I have a function with definition :

int foobar(char *ptr,...)

the function call is as follows :

int (*fooptr) (char *,...) = foobar;

I am not able to understand how is the function getting called …
Thanks in advance

Answer 1

That’s not a function call.

It is declaring a function pointer variable called fooptr that holds the address of the function.

To call that function via the pointer you would do e.g.:

int return_value = (*fooptr)(char_ptr, x, y, z);