Question

I have a general question regarding listeners.

Lets say I have two JTabbedPanes and both have a ChangeListener. They are both displayed and I want them both to show the same pane (index) so when a user changes the selected pane in one the other changes too.
In brief, one JTabbedPane listener changes the other JTabbedPane using setSelectedTab().
Obviously, the first listener will activate the second listener and the second will reactivate the first in an endless operation.

This will be solved with booleans.
Is there a smarter way to do it?
Is there a way to change a tab without triggering the Listener?
Is there a way to activate the listener only when a user changes it and not the code?

Thank you.

BTW: I always have the same questions with buttons. But with buttons I take the code from the listener and put it in a method. when One button needs to activate a button it calls its code. But in JTabbedPane it is different.

Answer 1

The simple solution is to act only when necessary. For example:

if(currentTab != desiredTab) {
  // change tab
}

That will prevent an infinite loop.

If you need to be able to switch the behavior on and off, then using a boolean flag isn’t a bad way to go about it. The alternative is the remove the listener, using removeChangeListener. The flag may be more performant as it may avoid memory allocation and deallocation, but a lot depends on the other details of your situation.