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Home/ Questions/Q 8420139
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T02:48:36+00:00 2026-06-10T02:48:36+00:00

I have a generator defined like this: def lengths(x): for k, v in x.items():

  • 0

I have a generator defined like this:

def lengths(x):
    for k, v in x.items():
        yield v['time_length']

And it works, calling it with

for i in lengths(x):
    print i

produces:

3600
1200
3600
300

which are the correct numbers.

However, when I call it like so:

somefun(lengths(x))

where somefun() is defined as:

def somefun(lengths):
    for length in lengths():  # <--- ERROR HERE
        if not is_blahblah(length): return False

I get this error message:

TypeError: 'generator' object is not callable

What am I misunderstanding?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T02:48:37+00:00Added an answer on June 10, 2026 at 2:48 am

    You don’t need to call your generator, remove the () brackets.

    You are probably confused by the fact that you use the same name for the variable inside the function as the name of the generator; the following will work too:

    def somefun(lengen):
        for length in lengen:
            if not is_blahblah(length): return False
    

    A parameter passed to the somefun function is then bound to the local lengen variable instead of lengths, to make it clear that that local variable is not the same thing as the lengths() function you defined elsewhere.

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