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Home/ Questions/Q 7562607
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T13:27:00+00:00 2026-05-30T13:27:00+00:00

I have a generator that I want to iterate through at two levels. The

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I have a generator that I want to iterate through at two levels. The first level is unevenly spaced, then I want to chunk the next level into groups of 5, say. I need it to be memory efficient and work on generator inputs, so I’m doing something like the following. I have to think there may be a better way? In particular, I don’t want the trailing Nones in the uneven length results.

import itertools

def dynamic_grouper(iterable, intervals):
    for i in intervals:
        inner_iter = list(itertools.islice(iterable, i)) # this is a "group"
        yield inner_iter

iterable = iter(xrange(100))
chunk_sizes = [22,30,38,10]

for i,group in enumerate(dynamic_grouper(iterable, chunk_sizes)):
    args = [iter(group)] * 5
    for item in itertools.izip_longest(fillvalue=None, *args):
        print "Group %i" % i
        print "Items %s" % list(item)
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  1. Editorial Team
    Editorial Team
    2026-05-30T13:27:02+00:00Added an answer on May 30, 2026 at 1:27 pm

    To avoid the Nones, you could use chunks:

    def chunks(seq, n):
        # https://stackoverflow.com/a/312464/190597 (Ned Batchelder)
        """ Yield successive n-sized chunks from seq."""
        for i in xrange(0, len(seq), n):
            yield seq[i:i + n]
    
    for i,group in enumerate(dynamic_grouper(iterable, chunk_sizes)):
        for item in chunks(group, 5):
            print "Group %i" % i
            print "Items %s" % list(item)
    
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