Question

I have a generic method something like:

public abstract T method<T>(int arg) where T : class, new();

Then I implement it in the child class

public MyType method<MyType>(int arg){
    MyType e = new MyType();

    e.doStuff (arg); // ERROR HERE

    return s;
}

But I can’t access MyType’s members… How come ? Is there something I can add to enable them or something ?

Thank you

Miloud

Answer 1

You can do like this (note that I have moved some of your generic parameters and constraints around).

public class MyType
{
    public void doStuff(int i){}
}
public abstract class ABase<T>where T : class, new()
{
    public abstract T method(int arg);
}

public class AChild : ABase<MyType>
{
    override public MyType method(int arg)
    {
        MyType e = new MyType();

        e.doStuff(arg); // no more error here

        return e;
    }
}