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Home/ Questions/Q 7826265
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T09:19:41+00:00 2026-06-02T09:19:41+00:00

I have a GUI ive created in Scala. Its very simple but I would

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I have a GUI ive created in Scala. Its very simple but I would like to modify the DSLOutput object from outside of DSLGUI. Does anyone know how I can call DSLOutput.append() from outside of the DSLGUI? Ive tried importing DSLGUI but I cant seems to figure out how to access DSLOutput.

package api
import swing._
import event._

object DSLGUI extends SimpleSwingApplication{

  def top = new MainFrame{
    title = "Computer Repair Advisory System"
    object Commands extends TextField(columns = 50)
    object DSLOutput extends TextArea(rows = 15, columns = 50)
    object SendCommand extends Button("Send")
    val CommandPanel = new FlowPanel{
      contents += Commands
      contents += SendCommand
    }
    contents = new BoxPanel(Orientation.Vertical){
        contents +=CommandPanel
        contents += DSLOutput
    }
    listenTo(SendCommand)
    reactions += {
      case ButtonClicked(SendCommand) =>
        DSLOutput append "Test "


    }
  }

}
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  1. Editorial Team
    Editorial Team
    2026-06-02T09:19:42+00:00Added an answer on June 2, 2026 at 9:19 am

    You would have to declare it in the scope of DSLGUI, rather than as a local object within your top method. Then you can access it with DSLGUI.DSLOutput.

    i.e.

    object DSLGUI extends SimpleSwingApplication {
    
      object DSLOutput extends TextArea(rows = 15, columns = 50)
    
      def top = new MainFrame {
        ...
      }
    }
    
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