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Home/ Questions/Q 8202559
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T07:13:43+00:00 2026-06-07T07:13:43+00:00

I have a hash (the real one is much bigger) parsed = {follower_count =>

  • 0

I have a hash (the real one is much bigger)

parsed = {"follower_count" => 500, "something_else" => "etc", "xyz" => "abc"}

and a class hanging around that looks like this

 class Company
   attr_accessor :followers

   def initialize(thehash)
      @followers = thehash['follower_count']
   end
 end

So lastly there is this code which throws the error before I can worry about anything else going wrong

>> parsed.map {|t| Company.new(t)}
TypeError: can't convert String into Integer
  from (irb):7:in `[]'
  from (irb):7:in `initialize'
  from (irb):12:in `new'
  from (irb):12
  from (irb):12:in `map'
  from (irb):12:in `each'
  from (irb):12:in `map'
  from (irb):12
  • 1 1 Answer
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T07:13:45+00:00Added an answer on June 7, 2026 at 7:13 am

    When you iterate over a Hash, the block gets an array as its argument and that array contains (in order) the key and value for one pair in the Hash. So, in here:

    parsed.map { |t| ... }
    

    t is actually a two element array and is usually written:

    parsed.map { |k, v| ... }
    

    Then, inside Company#initialize, you’re treating t as a Hash when it is actually a two element Array.

    You don’t want to use map on parsed at all, you just want to Company.new(parsed).

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