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Home/ Questions/Q 664429
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:35:57+00:00 2026-05-13T23:35:57+00:00

I have a HashMap where the key is a word and the value is

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I have a HashMap where the key is a word and the value is a number of occurrences of that string in a text. Now I’d like to reduce this HashMap to only 15 most used words (with greatest numbers of occurrences). Do you have any idea to do this efficiently?

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:35:57+00:00Added an answer on May 13, 2026 at 11:35 pm

    Using an array instead of ArrayList as suggested by Pindatjuh could be better,

    public class HashTest {
            public static void main(String[] args) {
                class hmComp implements Comparator<Map.Entry<String,Integer>> {
                    public int compare(Entry<String, Integer> o1,
                            Entry<String, Integer> o2) {
                        return o2.getValue() - o1.getValue();
                    }
                }
                HashMap<String, Integer> hm = new HashMap<String, Integer>();
                Random rand = new Random();
                for (int i = 0; i < 26; i++) {
                    hm.put("Word" +i, rand.nextInt(100));
                }
                ArrayList list = new ArrayList( hm.entrySet() );
                Collections.sort(list, new hmComp() );
                for ( int i = 0  ; i < 15 ; i++ ) {
                    System.out.println( list.get(i) );
                }
    
            }
        }
    

    EDIT reversed sorting order

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