Question

I have a header in which I declare a function. Then I create the function and try to use it but i get an error. It is by reference but I don’t know why it is not working.

struct.h

#ifndef LISTSTRUC_H_
#define LISTSTRUC_H_


template <class T> struct Array{
    int days;
    T * M;

Array( int size ) : days(size), M(new T[size])
{
}
~Array()
{
   delete[] M;
}
};

void currentDay();

template <class Expe>
void dummyData(Array<Expe> &);

#endif /* LISTSTRUC_H_ */

struct.cpp

void dummyData(Array <Expe> &A){
for(int i=0; i<31; i++){
    A.M[i].Expe::setObj((i*3),(i*1),(i*6),(i*2),(i*4),(i*5));
}
 }

M.cpp(Main cpp)

int main(){
//Main function of the program. no pre/ post condition.

    Array <Expe> A(31);   // Work space
    Array <Expe> B(31);   // Backup space

    dummyData(&A);         // error
 }

ERROR:

..\M.cpp:22:14: error: no matching function for call to 'dummyData(Array<Expe>*)'

Answer 1

dummyData(&A);

should be:

dummyData(A); 

Rationale:
Your function takes a reference not a pointer, &A means you are passing address of the type which can only be received in by a pointer to that type and you don’t have that overloaded version of the function, hence the error.