Question

I have a hex-string made from a unicode string with that function:

def toHex(s):
    res = ""
    for c in s:
        res += "%02X" % ord(c) #at least 2 hex digits, can be more
    return res

hex_str = toHex(u"...")

This returns a string like this one:

"80547CFB4EBA5DF15B585728"

That’s a sequence of 6 chinese symbols.
But

u"Knödel"

converts to

"4B6EF664656C"

What I need now is a function to convert this back to the original unicode. The chinese symbols seem to have a 2-byte representation while the second example has 1-byte representations for all characters. So I can’t just use unichr() for each 1- or 2-byte block.

I’ve already tried

binascii.unhexlify(hex_str)

but this seems to convert byte-by-byte and returns a string, not unicode. I’ve also tried

binascii.unhexlify(hex_str).decode(...)

with different formats. Never got the original unicode string.

Thank you a lot in advance!

Answer 1

This seems to work just fine:

binascii.unhexlify(binascii.hexlify(u"Knödel".encode('utf-8'))).decode('utf-8')

Comes back to the original object. You can do the same for the chinese text if it’s encoded properly, however ord(x) already destroys the text you started from. You’ll need to encode it first and only then treat like a string of bytes.