Question

I have a .htaccess file set up to define specific MIME types in directory root/a/b/, and all of the files are in the same directory.

I have a php file that wants to serve those files, in directory root/c/, and needs to determine the content-type as defined by the .htaccess file.

Is there any way to do this? PHP version is 5.1.6. mime_content_type returns text/plain, and I’d rather not try to parse the .htaccess file manually. I can move the file if necessary.

Answer 1

if you want to serve the files with php, why don’t you also define the mime types with php (eg. as an associative array with extension => mime type pairs)?

that being said, a possible way to achieve this without parsing the .htaccess file would be to let the php script do a request for the file in root/a/b and check the mime type in the response headers. if you serve the files with the HTTP wrapper, eg. fopen('http://example.com/a/b/file'), you get this automatically: you can access the response headers via $http_response_header or stream_get_meta_data – the mime type is in the Content-Type: header. if you open the file another way, you can still do a HEAD request first and check the response Content-Type (even though doing 2 requests for every file served seems overkill).