Question

I have a html form

<form action="process.php" method="post">

    <input type="checkbox" name="name[v1]"  />
    <input type="checkbox" name="name[v2]"  />
    <input type="checkbox" name="name[v3]"  />
    <input type="submit" name="update" value="update">
</form>

If they is only one check box is ticked then I only see that check box

Array
(
[\’v3\’] => on
)

If I have checked all three box then I see them all.

Array
(
    [\'v1\'] => on
    [\'v2\'] => on
    [\'v3\'] => on
)

Is they any way I can see all of my checkbox even if they are not checked.

process.php

foreach( $_POST['name'] as $k => $v )
{
   echo "key: ".$k;
}

Answer 1

Checkboxes and radio buttons are not passed on to the processing script if they don’t have a “checked” attribute set. This is HTML4 by design.

The only way you can set a state is using something like:

if(!isset($_POST['mycheckbox'])){ $_POST['mycheckbox'] = 0; }

or better yet:

$_POST['mycheckbox'] = isset($_POST['checkbox']);

Regarding radio buttons, you should only use the first version since radio buttons can have more than one value so instead of setting a TRUE/FALSE in them, you want to set a default value instead.

Another note, DISABLED elements are not posted, even if they have a value, you will never see them, this is another design feature of HTML4+