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Home/ Questions/Q 4019874
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T10:09:31+00:00 2026-05-20T10:09:31+00:00

I have a huge formatted file of the form: 29/01/2010 18:00 string1 string2 …..

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I have a huge formatted file of the form:

29/01/2010 18:00 string1 string2 .....

30/01/2010 18:30 string3 string4 .....

...

...

dd/mm/yyyy hh:MM strings strings....

I need to perform some statistics based on the dates.

So I would like to substitute the string dd/mm/yyyy hh:MM with epoch time in the file in order to perform simple manipulations.

I suppose that the best way is to use Perl, but I really don’t know where to start. Any hints?

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  1. Editorial Team
    Editorial Team
    2026-05-20T10:09:32+00:00Added an answer on May 20, 2026 at 10:09 am

    Just that? This quick-and-dirty one-liner should do:

    perl -MPOSIX -pwe 's{^(\d{2})/(\d{2})/(\d{4}) (\d{2}):(\d{2}) }{mktime(0,$5,$4,$1,$2-1,$3-1900)." "}e;'
    

    Feed it the file on standard input and it will output the changed version to standard output. All it does is look for lines that have “dd/mm/yyyy hh:mm ” at the start, and feed the date components to the mktime function from the POSIX module to get a unix timestamp.

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