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Home/ Questions/Q 9119321
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T05:22:04+00:00 2026-06-17T05:22:04+00:00

I have a input field as filter. At every keyup he calls a function

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I have a input field as filter. At every keyup he calls a function to post the input.val() to display the result in a table, this works fine. but if i’m typing a name “stackoverflow” he will post 13 times. I want that if he’s getting no input for 3 sec that he posts.

I thought that there was a function for (not a default function). And I do not want to auto-complete.

HTML:

<input type="text" id="filter" />

JavaScript:

$(document).ready(function(){
    $("#filter").keyup(function(){
        console.log('POST');
    });
 });

jsfiddle

I don’t wants a delay, because that will only “delays” it.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T05:22:06+00:00Added an answer on June 17, 2026 at 5:22 am

    Check out the jQuery throttle / debounce plugin

    It does exactly what you want

    $('input').keyup($.debounce(3000, function() { /* Post comes here */ }));
    
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