Question

I have a issue with my ajax form submission.I am dynamically submitting a form and using php at the server side to process it.This is the ajax success function.

   $.ajax({
                        type: "POST",
                        url: "register.php",
                        data: "uname="+uname+"&eid="+eid+"&pwd="+pass+"&cpwd="+cpass+"&country="+coun+"&contact="+contact,
                        dataType: "html",
                        success: function(data){
                            if(data!="error")
                            {   
                               //alert(data);
                                $("#user_status", window.parent.document).html("Welcome "+data+"&nbsp;&nbsp;|&nbsp;&nbsp;<a href='forum/logout.php'>Logout</a>");
                                if(window.parent.document.getElementById('post_user_name'))
                                    $("#post_user_name", window.parent.document).html(msg);
                                parent.$.fancybox.close();
                            }
                            if(data=="error")
                            {   
                                //alert(data);
                                $("#status").html("<span><center><font class='formright err_msg' style='width:176px;'>The user is already register with us.</font><center></span>");
                                return false;
                            }

Now if the user is valid he is logged in and f not there has to be an error like “Already exists”.The valid part works fine but for invalid I return an error from the php file but still my error message doesn’t show up and just error is printed on the screen.I am using fancybox for my forms(jquery fancybox)
PHP code is

        if($_POST['pwd']==$_POST['cpwd'])
            {
                $username   = $_POST['uname'];
                $email      = $_POST['eid'];
                $password   = md5($_POST['pwd']);
                $cpassword  = $_POST['cpwd'];
                $contact_no = $_POST['contact'];
                $country    = $_POST['country'];

                $cnt      =     $checkUser['cnt'];

                if($cnt!=0) 
                {
                    echo "error";
                    //exit;
                    /*$_SESSION['error_msg']    =   'Email Address already exists';
                    redirect_to_link("index.html");*/

                } 
                else
                {
                    //echo "entered here";
                    $userArray = array();
                    //$user = return_post_value($_POST['uname']);
                    $userArray['uname'] = return_post_value($_POST['uname']);
                    $userArray['email'] = return_post_value($_POST['eid']);
                    $userArray['password'] = md5(return_post_value($_POST['pwd']));
                    $userArray['contact_no'] = return_post_value($_POST['contact']);
                    $userArray['country'] = return_post_value($_POST['country']);

                    //print_r($userArray);
                    //exit;
                    $userObj->addUserValue($userArray);
                    $_SESSION['username']=  $userArray['uname'];            
                    echo $userArray['uname'];
                                  //    return $user;
                }

The echo $userArray[‘uname’]; part works but echo “error” doesn’t.Checked in Firebug response header,i can see the error word returned.
Can anyone throw some light on it?
Thanks

Answer 1

Use this to compare if($.trim(data)!=”error”)

And don’t recheck for if($.trim(data)==”error”)

use

if($.trim(data)!="error")
{
 //
}
else{
//
}