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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T22:07:14+00:00 2026-05-13T22:07:14+00:00

I have a Java application which is using a certain Java Runtime Environment. The

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I have a Java application which is using a certain Java Runtime Environment. The application uses it’s own launcher to startup the java virtual machine. No use of the java.exe, javaw.exe, javaws.exe binaries is being made — as the application seems to have it’s own launcher which is a different executable. This custom launcher is using the rest of the JRE files, such as bin/client/jvm.dll and rt.jar package etc.

Now, the problem is that I want to set a boot class path for this custom launcher. The custom launcher does not support the -Xbootclasspath command line parameter, like the default java.exe does.

Is there any way for me to set the boot class path now for this java runtime environment?

Thanks in advance.

Some things to keep in mind:

  1. I do not have the source of this application
  2. This is meant for self and personal debugging use only, not for distribution

Update: not getting a lot of replies, so let me rephrase my question. Books like http://my.safaribooksonline.com/0672326388/ch15lev1sec5 tell you to set the -Xbootclasspath, however how does one set such path when the application has it’s own JRE launcher directly loading the java libraries without usage of the default java.exe etc. executables?

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  1. Editorial Team
    Editorial Team
    2026-05-13T22:07:14+00:00Added an answer on May 13, 2026 at 10:07 pm

    If I understand you correctly, the custom launcher is some native code app that starts the JVM to run the Java app; i.e. java.exe etc, … but different.

    A couple of things that might work are:

    • adding your JAR to the Java installation’s “endorsed” directory, or

    • inserting your stuff inside the installation’s “rt.jar” file, or some other standard JAR.

    But in both cases, you could be changing the behavior of the Java installation for every application (and person) that uses it.

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