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Home/ Questions/Q 6549961
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:09:27+00:00 2026-05-25T12:09:27+00:00

I have a Java Application written that forwards selected files to an ssh server.

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I have a Java Application written that forwards selected files to an ssh server. I want this application to be automatically run every time windows starts.

I am aware that this question has been asked multiple times, and I have followed those leads. I have tried Java Service Wrapper (which is no longer accessible because of a dns problem), Apache Daemon, and JSL. Though I have at times been able to get the application installed as a service, I have never been able to get it to run properly on boot, or even start it manually from the command line.

My question is whether anyone is aware of a full first step through final step tutorial of how to make this work. I have come across a few things, but they all either assume that you have implemented something that they do not explain how to implement, or rely on applications that I do not have installed.

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:09:28+00:00Added an answer on May 25, 2026 at 12:09 pm

    I use Java Service Wrapper to install as windows or linux service: http://wrapper.tanukisoftware.com/doc/english/download.jsp

    ~> create one runnable JAR to your app.

    ~> Download the proper service wrapper (they are diffrent to windows and linux)

    ~> Configure the service in wrapper.conf

    Important: set wrapper.java.classpath correct (your jar must be here too)
    Set wrapper.java.mainclass with org.tanukisoftware.wrapper.WrapperSimpleApp
    Set wrapper.app.parameter.1 with the name of your main class, for example:

    wrapper.app.parameter.1=Main
    

    ~> Test the service as console (windows bat)

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