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Home/ Questions/Q 3677722
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T03:15:22+00:00 2026-05-19T03:15:22+00:00

I have a Java EE application and I want to validate a Date. With

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I have a Java EE application and I want to validate a Date.
With a String I do this:

import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;
...
@NotNull
@Size(min = 1, max = 255)
private String myString;

But now I have two dates which I want to validate. The user can in the frontend system write a String in a text field which will be transferred via JSON (I have to use text field, I can not use a datepicker).

So my backend does have this in my domain class:

@DateTimeFormat(pattern = "dd.MM.yy")
@Temporal(value=TemporalType.TIMESTAMP)
private Date myStartDate;

@DateTimeFormat(pattern = "dd.MM.yy")
@Temporal(value=TemporalType.TIMESTAMP)
private Date myEndDate;

I want to validate against the format “dd.MM.yyyy”. How can this be done?

And, I do not think so, but is there an automatic validation to check if the start date is before the end date? I only found @Future and @Past.

So the only solution is to use a @Pattern, a regular expression?!

Thank you in advance for your help, Best Regards.

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  1. Editorial Team
    Editorial Team
    2026-05-19T03:15:23+00:00Added an answer on May 19, 2026 at 3:15 am

    @DateTimeFormat is used during web data binding, when mapping request parameters onto an object (assuming you have enabled it with <mvc:annotation-driven/> or manually.) It’s not generally going to be used when deserializing JSON into an object. How are you reading in your JSON? What are you using to deserialize it? You can’t validate a java Date object after the fact for the formatting, you have to check up front before deserialization.

    There are no multi-field constraints built in. You’ll want to write your own type level constraint if you want to compare two properties on an object.

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